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-0.48x^2+0.2x+1=0
a = -0.48; b = 0.2; c = +1;
Δ = b2-4ac
Δ = 0.22-4·(-0.48)·1
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{1.96}}{2*-0.48}=\frac{-0.2-\sqrt{1.96}}{-0.96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{1.96}}{2*-0.48}=\frac{-0.2+\sqrt{1.96}}{-0.96} $
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